Algebraic Structures | Solving the Matrix Commutator MX = XM | is 2 x 2 matrices with real number well-defined ?

Algebraic Structures | Question-4

Algebraic Structures | Question-4: Matrix Commutator Problem

Question

Let A be the set of all 2 × 2 real matrices. Consider the specific matrix:
\[ M = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} \]

Definition of Set B

The set B is defined as:
\[ B = \{ X \in A \mid MX = XM \} \]
This defines the set of all matrices that commute with matrix M.

Question: If we let \( X = \begin{pmatrix} p & q \\ r & s \end{pmatrix} \), what conditions must p, q, r, s satisfy for X to belong to B? That is, when does \( MX = XM \)?

Solution

Understanding Matrix Commutation

Two matrices commute if their product is the same regardless of order:
\[ MX = XM \]
To find all matrices X that commute with M, we need to solve this equation for X.
Step 1: Multiply Both Ways

First, compute the product \( MX \):

\[ MX = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} \begin{pmatrix} p & q \\ r & s \end{pmatrix} = \begin{pmatrix} p+r & q+s \\ r & s \end{pmatrix} \]

Then compute the product \( XM \):

\[ XM = \begin{pmatrix} p & q \\ r & s \end{pmatrix} \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} = \begin{pmatrix} p & p+q \\ r & r+s \end{pmatrix} \]
Step 2: Set Products Equal

For \( X \) to commute with \( M \), we require \( MX = XM \). Setting the matrices equal gives:

\[ \begin{pmatrix} p+r & q+s \\ r & s \end{pmatrix} = \begin{pmatrix} p & p+q \\ r & r+s \end{pmatrix} \]
Important Note: Two matrices are equal if and only if all their corresponding entries are equal.
Step 3: Compare Corresponding Entries

By comparing corresponding matrix entries, we obtain the following system of equations:

Entry-by-Entry Comparison

\[ \begin{aligned} &(1,1): \quad p + r = p \\ &(1,2): \quad q + s = p + q \\ &(2,1): \quad r = r \\ &(2,2): \quad s = r + s \end{aligned} \]

Simplifying these equations:

  1. Top-left: \( p + r = p \) gives \( \boxed{r = 0} \)
  2. Top-right: \( q + s = p + q \) gives \( \boxed{s = p} \)
  3. Bottom-left: \( r = r \) is automatically satisfied
  4. Bottom-right: \( s = r + s \) is consistent with \( r = 0 \)
Step 4: General Form of Commuting Matrices

From the conditions \( r = 0 \) and \( s = p \), every matrix that commutes with \( M \) must have the form:

\[ X = \begin{pmatrix} p & q \\ 0 & p \end{pmatrix} \]

where \( p \) and \( q \) can be any real numbers.

Key Observation: These matrices form a 2-dimensional vector space parameterized by p and q.

Final Solution

The necessary and sufficient conditions for \( X \) to commute with \( M \) are:
\[ \boxed{r = 0 \quad \text{and} \quad s = p} \]
Therefore, the set \( B \) consists of all matrices of the form:
\[ B = \left\{ \begin{pmatrix} p & q \\ 0 & p \end{pmatrix} \mid p, q \in \mathbb{R} \right\} \]
\[ X = \begin{pmatrix} p & q \\ 0 & p \end{pmatrix} \]
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